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Unit 33 · Bahagi Lagi
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Unit 33

Bahagi Lagi

Pilih gandaan pembahagi yang paling besar tetapi tidak melebihi nombor asal.

Bahagi Lagi
Langkah 1

Cari gandaan terbesar

Pilih gandaan pembahagi yang paling besar tetapi tidak melebihi nombor asal.

23 ÷ 5 · 4 × 5 = 20
Gandaan terbesar = 最大的倍数
有余数的除法,先在除数的乘法表里找最大但不超过原数的那个数。算 23 ÷ 5,5 的乘法表有 20 和 25。25 超过 23,所以选 20,也就是 4 × 5 = 20。
例子:17 ÷ 3:15 不超过 17,18 太大,选 5 × 3 = 15。
注意:选的倍数不能比原来的数大,超过了就分不出来。
Gandaan terbesar = Largest multiple
For a division with a remainder, find the largest multiple of the divisor that is not more than the starting number. For 23 ÷ 5, the table of 5 has 20 and 25. Since 25 is too big, choose 20, which is 4 × 5 = 20.
Example: 17 ÷ 3: 15 fits but 18 is too big, so use 5 × 3 = 15.
Watch out: The multiple must not be bigger than the starting number.
Langkah 2

Tolak untuk mendapat baki

Selepas menggunakan 20 daripada 23, baki ialah 3. Jadi 23 ÷ 5 = 4 baki 3. Dalam bentuk lazim, 4 ditulis di atas dan baki 3 di bawah.

23 − 20 = 3 baki
Tolak untuk baki = 减出余数
找到最大的倍数后,用原来的数减去它,就得到余数。23 − 20 = 3,所以 23 ÷ 5 = 4 余 3,意思是分成 4 组,每组 5 个,还剩 3 个。余数是分完后剩下的数量。
例子:17 ÷ 3:17 − 15 = 2,所以 17 ÷ 3 = 5 余 2。
注意:答案要写两部分:商和余数,只写一个数不完整。
Tolak untuk baki = Subtract to find the remainder
After finding the largest multiple, subtract it from the starting number to get the remainder. 23 − 20 = 3, so 23 ÷ 5 = 4 remainder 3. That means 4 groups of five with 3 left over.
Example: 17 ÷ 3: 17 − 15 = 2, so 17 ÷ 3 = 5 remainder 2.
Watch out: Write both parts of the answer, the groups and the remainder; one number alone is incomplete.
Langkah 3

Baki mesti lebih kecil

Baki sentiasa lebih kecil daripada pembahagi. Bahagi dengan 10: digit puluh ialah jawapan dan digit sa ialah baki, contohnya 56 ÷ 10 = 5 baki 6.

baki < pembahagi
Baki lebih kecil = 余数要更小
余数一定要比除数小。如果余数等于或大于除数,表示还能再分出一组,答案就没算完。例如 14 ÷ 4 写成 2 余 6,6 比 4 大,还能再分一组。
例子:26 ÷ 4 = 6 余 2,2 比 4 小,正确。
注意:算完后一定要把余数和除数比一比。
Baki lebih kecil = Remainder must be smaller
The remainder must always be smaller than the divisor. If it is equal or bigger, one more group can still be made, so the division is not finished. For example, writing 14 ÷ 4 as 2 remainder 6 is wrong, because 6 is bigger than 4.
Example: 26 ÷ 4 = 6 remainder 2, and 2 is smaller than 4, so it is correct.
Watch out: Always compare the remainder with the divisor before you finish.
Semak cepat · Soalan 1 / 2

Cuba sendiri

Pilih jawapan. Jika belum tepat, baca petunjuk dan cuba lagi.

19 ÷ 4 = __

Bahagi dengan baki = 有余数的除法
题目问 19 ÷ 4,答案要有商和余数两部分。先在 4 的乘法表里找不超过 19 的最大数,再用 19 减去它得到余数。最后检查:余数要比 4 小,而且“商 × 4 + 余数”要等于 19。
例子:22 ÷ 4 = 5 余 2,检查 5 × 4 + 2 = 22。
注意:用乘法加余数检查时,记得先乘再加。
Bahagi dengan baki = Division with remainder
The question asks for 19 ÷ 4, and the answer has two parts: the number of groups and the remainder. Find the largest multiple of 4 up to 19 and subtract it. Check that the remainder is smaller than 4 and that groups × 4 + remainder makes 19.
Example: 22 ÷ 4 = 5 remainder 2. Check: 5 × 4 + 2 = 22.
Watch out: When checking, multiply first and then add the remainder.
Semak cepat · Soalan 2 / 2

Cuba sendiri

Pilih jawapan. Jika belum tepat, baca petunjuk dan cuba lagi.

23 ÷ 5 = __

Baki dan pembahagi = 余数与除数
题目问 23 ÷ 5,要选出完全正确的商和余数。先在 5 的乘法表里找最接近又不超过 23 的数,用 23 减去它得到余数。再做两项检查:“商 × 5 + 余数”算回 23,而且余数比 5 小。
例子:38 ÷ 5 = 7 余 3,检查 7 × 5 + 3 = 38。
注意:两项检查都要做,只算回原来的数还不够。
Baki dan pembahagi = Remainder and divisor
The question asks for 23 ÷ 5, and needs both groups and remainder right. Subtract the largest multiple of 5 up to 23. Then check two things: groups × 5 + remainder gives 23, and the remainder is smaller than 5.
Example: 38 ÷ 5 = 7 remainder 3. Check: 7 × 5 + 3 = 38.
Watch out: Do both checks; getting back the starting number alone is not enough.
Ringkasan

Syabas!

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Ingat: cari gandaan terbesar; tolak untuk mendapat baki; baki mesti lebih kecil.

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