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Unit 8 · Bilang Nombor
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Unit 8

Bilang Nombor

Tambah nilai yang sama setiap kali. Contohnya, bilang menaik sepuluh-sepuluh: 320, 330, 340, 350.

Bilang Nombor
Langkah 1

Bilang menaik

Tambah nilai yang sama setiap kali. Contohnya, bilang menaik sepuluh-sepuluh: 320, 330, 340, 350.

320330340350+10+10+10450455460465−5−5−5
Bilang menaik = 往上数
往上数就是每次加上同样的数。这一页每次加 10:320、330、340、350,十位每次多 1,个位不变。
例子:每次加 100:215、315、415、515,215 + 100 = 315。
注意:加 10 时改变的是十位,别把个位也加 1。
Bilang menaik = Count up
Counting up means adding the same jump each time. Here the jump is 10: 320, 330, 340, 350. The tens digit grows by 1 each time while the ones digit stays the same.
Example: Jump by 100: 215, 315, 415, 515, since 215 + 100 = 315.
Watch out: When adding 10, only the tens digit changes; the ones digit stays put.
Langkah 2

Bilang menurun

Tolak nilai yang sama setiap kali. Contohnya, bilang menurun lima-lima: 465, 460, 455, 450.

465 → 460 → 455 → 450
Bilang menurun = 往下数
往下数就是每次减去同样的数。这一页每次减 5:465、460、455、450,个位在 5 和 0 之间轮流变化。
例子:每次减 2:136、134、132、130,136 − 2 = 134。
注意:从 460 减 5 会跨过十位,得到 455,十位也要减 1。
Bilang menurun = Count down
Counting down means taking away the same jump each time. Here the jump is 5: 465, 460, 455, 450. The ones digit switches between 5 and 0.
Example: Jump back by 2: 136, 134, 132, 130, since 136 − 2 = 134.
Watch out: From 460, taking 5 crosses into the tens, so the next number is 455.
Langkah 3

Cari selang dahulu

Bezakan dua nombor bersebelahan untuk mengetahui selangnya.

208, 212 · selang 4
Cari selang dahulu = 先找间隔
要知道每次跳多少,就用后一个数减前一个数。208 到 212:212 − 208 = 4,所以间隔是 4。
例子:530、550、570:550 − 530 = 20,间隔是 20,下一个是 570 + 20 = 590。
注意:至少检查两对相邻的数,确定间隔每次都一样。
Cari selang dahulu = Find the jump first
To know the jump, subtract the earlier number from the next one. From 208 to 212: 212 − 208 = 4, so the jump is 4.
Example: 530, 550, 570: 550 − 530 = 20, so the jump is 20 and the next number is 570 + 20 = 590.
Watch out: Check at least two pairs of neighbours to be sure the jump stays the same.
Semak cepat · Soalan 1 / 2

Cuba sendiri

Pilih jawapan. Jika belum tepat, baca petunjuk dan cuba lagi.

Lengkapkan: 240, 250, 260, __

Lengkapkan = 填完数列
这题给 240、250、260,要找下一个数。先找间隔:250 − 240 = 10,再用最后一个数 260 加上这个间隔。
例子:515、525、535,下一个是 535 + 10 = 545。
注意:看清楚这里是十位在变,不是个位在变。
Lengkapkan = Complete the list
The question gives 240, 250, 260 and asks for the next number. Find the jump first: 250 − 240 = 10. Then add that jump to the last number, 260.
Example: 515, 525, 535, so the next number is 535 + 10 = 545.
Watch out: Here the tens digit changes, not the ones digit.
Semak cepat · Soalan 2 / 2

Cuba sendiri

Pilih jawapan. Jika belum tepat, baca petunjuk dan cuba lagi.

Lengkapkan: 615, 610, 605, __

Lengkapkan bilang menurun = 填完往下数
这题给 615、610、605,数越来越小。先算间隔:615 − 610 = 5,所以每次减 5,再用 605 减 5。往下数的时候,每一个数都要比前一个少同样的数量,最后再检查一次间隔是否都一样。
例子:340、335、330,下一个是 330 − 5 = 325。
注意:数在变小,不能加上间隔,要减去。
Lengkapkan, bilang menurun = Complete a count down
The question gives 615, 610, 605, and the numbers are getting smaller. The jump is 615 − 610 = 5, so take 5 away from 605 to find the next one.
Example: 340, 335, 330, so the next number is 330 − 5 = 325.
Watch out: The list goes down, so subtract the jump instead of adding it.
Ringkasan

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Ingat: bilang menaik; bilang menurun; cari selang dahulu.

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